#8 Amplitude variation in Damped Oscillation | SHM | IIT JEE Physics | #shorts

Shm - Damped Oscillation

If initial amplitude during a damped oscillation of mass m is 12 cm and after 2s it reduces to 6cm then find damping constant(b)

The amplitude of a damped oscillation decreases to 0.8 times its original magnitude in 4s. In another 12s, it will decrease to n time its original magnitude. Find the value of n.

For the damped oscillator of Fig. 15.20, m= 250g, k= 85N/m, and b= 70g/s How long does it take for the amplitude of the damped oscillations to drop to half its initial value?

A particle is executing SHM of amplitude 10 cm. Its time period of oscillation is pi seconds. The velocity of the particle when it is 2 cm from extreme position is

A horizontal platform with an object placed on it is executing S.H.M. in the vertical direction. The amplitude of oscillation is 2.5 cm. If the object is not detached from the platform, then the least period of these oscillations will be, (g=10m//s^(2))

Amplitude of a damped oscillator decreases up to 0.6 times of its initial value in 5 seconds. In next 10 seconds, it decreases upto 'alpha' times of its intial value where 'alpha' is equal to ?

For SHM to take place force acting on the body should be proportional to -x or F =- kx . If A be the amplitude then energy of oscillation is 1//2KA^(2) . The amplitude of oscillation is

The amplitude of a damped oscillator becomes half in one minutes. The amplitude after 3 minutes will be 1/x times of the original . Determine the value of x.