cm to nm

Convert a pressure of 76 cm of mercury into Nm^(-2) . Density of mercury is 13.6 gm//c c .

How much work will be done in increasing the diameter of a soap bubble from 2 cm to 5 cm. Surface tension of soap solution is 3.0xx10^(-1) Nm^(-1) .

Work done in increasing the size of a soap bubble from a radius of 3cm to 5cm is nearly (Surface tension of soap solution =0.03Nm^-1 )

Work done in increasing the size of a soap bubble from a radius of 3 cm to 5 cm is nearly. (surface tension of soap solution = 0.3 Nm^(-1))

In the adjoining figure , point A is the centre of the circle , AN=10cm . Line NM is tangent at M. Determine the radius of the circle , if MN =5 cm.

Calculate the surface tension of a liquid if 5 xx 10^(-3)Nm^(-1) of work is done to increase the surface area of a liquid film from 4 cm xx 3" cm to 8 cm "xx "5 cm."

Find the work done in blowing a soap bubble of surface tension 0.06 Nm^(-1) from 2 cm radius to 5 cm radius.

The work done in blowing a soap bubble of surface tension 0.60 Nm^(-1) from 2 cm radius to 5 cm radius is