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If 75% of a first order reaction completed in 15 min . Then 90% of the same reaction completed in

A First order reaction is 50% complete in 69.3 minutes. Time required for 90% completion for the same reaction is

(a) For a first order reaction, show that time required for 99% completion is twice the time required for the completion of 90% of reaction. (b) Rate constant 'K' of a reaction varies with temperature 'T' according to the equation : logK=logA-E_a/(2.303R)(1/T) Where E_a is the activation energy. When a graph is plotted for log k Vs 1/(T) a straight line with a slope of -4250 K is obtained. Calculate E_a for the reaction. ( R=8.314JK^(-1)mol^(-1) )

The time for 90% of a first order reaction to complete is approximately