Analysis Of Interference Pattern|Fringe Width|Quiz

Analysis Of Interference Pattern|Question

Mathematical Analysis Of Interference

Shape Of Interference Fringes In Ydse

In an interference pattern of two wave fringe width is beta . If the frequency of source is doubled then fringe width will become :

In Young's doubles slit experiment for producing interference pattern the fringe width depends on i) wave length ii) distance between the two slits iii) distance between the screen and the slits iv) distance between source and the slits

In Young's double sit experiment two light sources when placed at a distance d apart, then Interference pattem having fringe width w. If the distance between the sources is reduced to d/3, then fringe width would be

Assertion (A) : The maximum intensity in interference pattern is four times the intensity in interference pattern is four times the intensity due to each slit of equal width. Reason (R ) : Intensity is directly proportinal to square of amplitude.

Assertion : The fringe closest on either side of the central white fringe in case of interference pattern due to white light is red and the farthest appears blue. Reason : The interference patterns due to different component colours of white light overlap.

Two coherent sources of intensity ratio 1:4 produce an interference pattern. The fringe visibility will be

Laser light of wavelength 630 nm incident on a pair of slits produces an interference pattern in which the bright fringes are separated by 8.1 mm. A second laser light produces an interference pattern in which the fringes are separated by 7.2 mm. Calculate the wavelength of the second light.