Size of nucleus

From Rutherford's experiment, estimated sizes of nucleus and atom are

Large angle scattering of alpha- particle led Rutherford to the discovery of atomic nucleus. It is the tiny central core of every atom in which entire positive charge of the atom is concentrated. The distance of closet approach of alpha particle from the nucleus is r_(theta)=((Ze)(2e))/(4pi epsilon_(theta)((1)/(2)mv^(2))) This distance r_(theta) gave him the order of size of nucleus. Read the above passage and answer the followign question: (i) What is the distance of closet approach of an alpha particle of energy 7.7 MeV from gold nucleus (z=79)? (ii) What is the implication of this relation in day to day life?

The size of a nucleus is of the order of-

Which unit is used to measure size of a nucleus ?

Name the unit used to measure size of a nucleus and express it in metre

If the size of a nucleus (~~10^(-15)m) is scaled up to the tip of a sharp pin (~~ 10^(-5)m), what roughly is the size of an atom?

Statement-1: Distance of closest approach of alpha particle to the nucleus is always greater than the size of the nucleus. Statement-2: Strong nuclear repulsion does not allow alpha particle to reach the surface of nucleus.