A body of mass 1kg begins to move under ...

A body of mass `1kg` begins to move under the action of a time dependent force `F=(that i+3t^(2)hatj)N`, where `vec i` and `vec j` are the unit vectors along `x` and `y` axis.The power developed by above force,at the time `t=2s`,will be

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A body of mass 1 kg begins to move under the action of a time dependent force F=(2that(i)+3t^(2)hat(j))N, "where" hat(i)and hat(j) are unit vector along x and y axis. What power will be developed by the force at the time?

A body of mass 1 kg begins to move under the action of a time dependent force vec F = (2 t hat I + 3 t^(2) hat j) N , where hat i and hat j are unit vectors along x-and y-axes. What power will be developed by the force at the time t ?

A body of mass 1kg begins to move under the actio of a time dependent force vec(F)=(2t hat(i)+3t^(2) hat(j))N , where hat (i) and hat(j) are unit vectors along X and Y axis. What does will be developed by the source at time t ?

If vec(i) and vec(j) are unit vectors along x-axis and y-axis respectively, the magnitude of vector vec(i)+vec(j) will be :-

An object of mass 2 kg at rest at origin starts moving under the action of a force vec(F)=(3t^(2)hat(i)+4that(j))N The velocity of the object at t = 2 s will be -

The unit vector along vec(A)= 2 hat i + 3 hat j is :

A particle moves along x - axis under the action of a position dependent force F=(5x^(2)-2x)N . Work done by force on the particle when it moves from origin to x = 3 m is

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