The graph between two temperature scales `A` and `B` is shown in Fig. Between upper fixed point and lower fixed point there are `150` equal divisions on scales `A` and `100` on scale `B`. The relation between the temperature in two scales is given by_

Options

A. `(t_(P))/(100)=(18)/(150)`
B. `(t_(Q))/(150)=(t_(P)-180)/(100)`
C. `(t_(P))/(180)=(t_(Q)-40)/(100)`
D. `(t_(Q))/(100)=(t_(P)-30)/(150)`

Answer

D