Home
Class 12
PHYSICS
A spherical drop of liquid splits into 1...

A spherical drop of liquid splits into `1000` identical spherical drops.If `mu_i` is the surface energy of the original drop and `mu_f` is the total surface energy of the resulting drops,the (gnoring evaporation), `(mu_(f))/(mu_(i))=((10)/(x))`.The value of `x` is

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the surface energy of the spherical drops before and after the split. ### Step 1: Understand the volume conservation When a spherical drop of liquid splits into 1000 identical smaller drops, the volume of the original drop must equal the total volume of the smaller drops. Let: - \( R \) = radius of the original drop - \( r \) = radius of each smaller drop The volume of the original drop is given by: \[ V_i = \frac{4}{3} \pi R^3 \] The volume of one smaller drop is: \[ V_f = \frac{4}{3} \pi r^3 \] Since there are 1000 smaller drops, the total volume of the smaller drops is: \[ V_{total} = 1000 \times V_f = 1000 \times \frac{4}{3} \pi r^3 \] Setting the volumes equal gives: \[ \frac{4}{3} \pi R^3 = 1000 \times \frac{4}{3} \pi r^3 \] Cancelling \( \frac{4}{3} \pi \) from both sides: \[ R^3 = 1000 r^3 \] ### Step 2: Relate the radii Taking the cube root of both sides: \[ R = 10 r \] ### Step 3: Calculate the surface energy The surface energy \( \mu \) of a spherical drop is given by: \[ \mu = \sigma \times A \] where \( \sigma \) is the surface tension and \( A \) is the surface area. The surface area of the original drop is: \[ A_i = 4 \pi R^2 \] Thus, the surface energy of the original drop is: \[ \mu_i = \sigma \times 4 \pi R^2 \] For the smaller drops, the surface area of one drop is: \[ A_f = 4 \pi r^2 \] So, the total surface energy of the 1000 smaller drops is: \[ \mu_f = 1000 \times \sigma \times 4 \pi r^2 \] ### Step 4: Find the ratio of surface energies Now, we need to find the ratio \( \frac{\mu_f}{\mu_i} \): \[ \frac{\mu_f}{\mu_i} = \frac{1000 \times \sigma \times 4 \pi r^2}{\sigma \times 4 \pi R^2} \] Cancelling \( \sigma \) and \( 4 \pi \): \[ \frac{\mu_f}{\mu_i} = \frac{1000 r^2}{R^2} \] ### Step 5: Substitute \( R \) in terms of \( r \) From Step 2, we have \( R = 10r \), thus: \[ R^2 = (10r)^2 = 100r^2 \] Substituting this into the ratio: \[ \frac{\mu_f}{\mu_i} = \frac{1000 r^2}{100 r^2} = \frac{1000}{100} = 10 \] ### Step 6: Relate to the given equation We are given: \[ \frac{\mu_f}{\mu_i} = \frac{10}{x} \] Setting the two expressions equal: \[ 10 = \frac{10}{x} \] ### Step 7: Solve for \( x \) Cross-multiplying gives: \[ 10x = 10 \] Thus: \[ x = 1 \] ### Final Answer The value of \( x \) is \( 1 \). ---
Promotional Banner

Topper's Solved these Questions

  • JEE MAINS 2022

    JEE MAINS PREVIOUS YEAR|Exercise PHYSICS (SECTION -B)|10 Videos

Similar Questions

Explore conceptually related problems

A spherical liquid drop of radius R is split up ino 8 equal droplets .If T is the surface tension of the liquid , then the work done in this process is

A liquid drop having surface energy E is spread into 512 droplets of same size. The final surface energy of the droplets is

The work done to split a liquid drop id radius R into N identical drops is (taken sigma as the surface tension of the liquid)

If a million tiny droplets of water of the same radius coalesce into one larger drop, the ration of the surface energy of the large drop to the total surface energy of all the droplets will be

8000 identical water drops are combined to form a big drop then the ratio to the final surface energy to the initial surface energy. If all the drops together is

8000 identical water drops combine together to form a big drop. Then the ratio of the initial surface enrgy of all the initial surface energy of all the drops together is

The surface energy of a liquid drop is U . If it is sprayed into 125 identical drops , then the total surface energy will be

A liquid drop of diameter D breaks upto into 27 small drops of equal size. If the surface tension of the liquid is sigma , then change in surface energy is

JEE MAINS PREVIOUS YEAR-JEE MAINS 2023 JAN ACTUAL PAPER-Question
  1. Two long parallel wires carrying current 8A and 15A in opposite direct...

    Text Solution

    |

  2. If a solid sphere of mass 5kg and a disc of mass 4kg have the same rad...

    Text Solution

    |

  3. A spherical drop of liquid splits into 1000 identical spherical drops....

    Text Solution

    |

  4. A nucleus disintegrates into two smaller parts,which have their veloci...

    Text Solution

    |

  5. A series LCR circuit is connected to an AC source of 220V,50Hz.The cir...

    Text Solution

    |

  6. Speed of an electron Bohr's 7^( th) orbit for Hydrogen atom is 3.6time...

    Text Solution

    |

  7. A sinusoidal carrier voltage is amplitude modulated.The resultant ampl...

    Text Solution

    |

  8. The charge flowing in a conductor changes with time as Q(t)=alpha t-be...

    Text Solution

    |

  9. Choose the correct relationship between Poisson ratio (sigma),Bulk mod...

    Text Solution

    |

  10. The output waveform of the given logical circuit for the following inp...

    Text Solution

    |

  11. A small object at rest,absorbs a light pulles of power 20mW and durati...

    Text Solution

    |

  12. Two isolated metallic solid spheres of radii R and 2R are charged such...

    Text Solution

    |

  13. In a series LR circuit with X(L)=R,power factor is P(1).If a capacitor...

    Text Solution

    |

  14. Match Column-I with Column-II: Choose the correct answer from the o...

    Text Solution

    |

  15. The figure represents the momentum time (p-t) curve for a particle mov...

    Text Solution

    |

  16. A person has been using speetacles of power -1.0 Dioptre for distant v...

    Text Solution

    |

  17. The height of liquid column raised in a capillary tube of certain radi...

    Text Solution

    |

  18. Heat is given to an ideal gas in an isothermal process. A.Internal e...

    Text Solution

    |

  19. The magnetic moments associated with two closely wound circular coils ...

    Text Solution

    |

  20. A massless square loop,of wire of resistance 10Omega,supporting a mass...

    Text Solution

    |