A lift of mass `M=500kg` is descending with speed of `2ms^(-1)`.Its supporting cable begins to slip thus allowing it to fall with a constant acceleration of `2ms^(-2)`.The kinetic energy of the lift at the end of fall through to a distance of `6m` will be ____ kJ

An elevator cab of mass m=500 kg is descending with speed v_(i)=4.0m//s when its supporting cable begins to slip, allowing it to fall with constant acceleration vec(a)=vec(g)//5 . What is the cab's kinetic energy at the end of the 12 m fall ?

An elevator cab of mass m=500 kg is descending with speed v_(i)=4.0m//s when its supporting cable begins to slip, allowing it to fall with constant acceleration vec(a)=vec(g)//5 . During the fall through a distance d=12 m, what is the work W_(g) done on the cab by the gravitational force vec(F)_(g) ?

A thin ring of mass 1kg and radius 1m is rolling at a speed of 1ms^(-1) . Its kinetic energy is

The mass of a lift if 600kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is :

A man weighing 60 kg is in a lift moving down with an acceleration of 1.8" ms"^(-2) . The force exerted by the floor on him is

The mass of a lift is 600 kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is-

A boy whose mass is 50 kg stands on a spring balance inside a lift. The lift starts to ascent with an acceleration of 2ms^(-2) . The reading of the machine or balance (g=10ms^(-2)) is

A rocket with a lift mass of 10,000 kg is blasted upwards with an acceleration of 10ms^(-2) . Calculate the initial thrust of the blast