The equation of a circle is given by `x^(2)+y^(2)=a^(2)`,where `a` is the radius.If the equation is modified to change the origin other than `(0,0)`,then find out the correct dimensions of `A` and `B` in a new equation :
`(a-At)^(2)(y-(1)/(B))^(2)=a^(2).` The dimensions of `t` is given as `[T^(-1)]`.

Options

A. `A = [LT], B = [L^(–1)T^(–1)]`
B. ` A = [L^(–1)T], B = [LT^(–1)] `
C. `A = [L^(–1)T^(–1) ], B = [LT]`
D. `A = [L^(–1)T^(–1)], B = [LT^(–1)]`

Answer

A