A null point is found at `200cm` in potentiometer when cell in secondary circuit is shunted by `5Omega`.When a resistance of `15Omega` is used for shunting,null point moves to `300cm`.the internal resistance of the cell is _____`Omega`.

In potentiometer experiment, a cell is balanced by length 120cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In potentiometer experiment, a cell is balanced by length 120 cm. When a cell is shunted by resistance of 5Omega , the balancing length is 80 cm. The internal resistance of cell is

In an experiment with a potentiometer to measure the internal resistance of a cell. when the cell in the secondary circuit is by shounted by 5 Omega , the null point is at 220 cm . When the cell is shunted by 20 Omega the null point is at 300 cm . Find the internal resistance of the cell.

A cell of e.m.f. 1.2 V is balanced by 150 cm of potentiometer wire. When the cell is shunted by a resistance of 4 Omega , the balancing length is reduced by 30 cm. What is the internal resistance of the cell ?

In a potentiometer arrangement for determining the emf of cell, the balance point of the cell in open circuit is 350 cm. When a resistance of 9 Omega is used in the external circuit of cell , the balance point shifts to 300 cm. Determine the internal resistance of the cell.