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A paddle wheel is connected with a block of mass 10kg as shown in figure. The wheel is completely immersed in liquid of heat capacity 400 J//K . The container is adiabatic. For the time interval in which block goes down 1m slowly calculate (a) Work done on the liuid (b) Heat supplied to the liquid (c ) Rise in the temperature of the liquid Neglect the heat capacity of the container and the paddle. (g = 10 m//s^(2))

In the arrangement shown in figure, the piston can smoothly move inside the cylinder. The mass of the piston is m = 100 g and its cross sectional area is A = 10 cm^(2) . The length of air column at temperature of T = 27^(@)C is 10 cm. Overall length of the cylinder is 20.4 cm. The container is turned upside down and the length of the air column in equilibrium was found to be l at 27^(@)C . Take R = (25)/(3)J mol^(-1) K^(-1) and assume air to be diatomic gas. g = 10 m//s^(2) , atmospheric pressure is 1.01 xx 10^(5) Nm^(2) (a) Find l (b) If the air in the container is supplied heat in upside down position, the piston slowly begins to move down, and ultimately it gets ejected out of the cylinder. Calculate the amount of heat that the air must absorb for the piston to come out.