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The average kinetic energy of a molecule...

The average kinetic energy of a molecule of the gas is

A

proportional to absolute temperature

B

proportional to volume

C

dependent on the nature of the gas

D

proportional to pressure

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To find the average kinetic energy of a molecule of a gas, we can use the formula derived from the kinetic theory of gases. The average kinetic energy (KE) of a single molecule of an ideal gas is given by the equation: \[ KE = \frac{3}{2} k T \] where: - \( k \) is the Boltzmann constant (\(1.38 \times 10^{-23} \, \text{J/K}\)), - \( T \) is the absolute temperature of the gas in Kelvin. ### Step-by-Step Solution: 1. **Identify the Formula**: The average kinetic energy of a molecule of an ideal gas is given by the formula \( KE = \frac{3}{2} k T \). 2. **Understand the Variables**: - \( k \) (Boltzmann constant) is a physical constant that relates the average kinetic energy of particles in a gas with the temperature of the gas. - \( T \) is the absolute temperature measured in Kelvin. 3. **Substituting Values**: If you have a specific temperature \( T \) for the gas, you can substitute that value into the equation to find the average kinetic energy. 4. **Calculate**: If \( T \) is provided, for example, if \( T = 300 \, K \): \[ KE = \frac{3}{2} (1.38 \times 10^{-23} \, \text{J/K}) (300 \, K) \] \[ KE = \frac{3}{2} (4.14 \times 10^{-21} \, J) \] \[ KE = 6.21 \times 10^{-21} \, J \] 5. **Conclusion**: The average kinetic energy of a molecule of the gas at \( 300 \, K \) is approximately \( 6.21 \times 10^{-21} \, J \).
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