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A light of energy 12.75eV is incident on...

A light of energy `12.75eV` is incident on a hydrogen atom in its ground state.The atom absorbs the radiation and reaches to one of its excited states.The angular momentum of the atom in the excited state is `(x)/(pi)times10^(-17)eV`.The value of `x` is (use `h=4.14times10^(-15)eVs,c=3times10^(8)ms^(-1))`

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