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In Figure,BM and DN are both perpendiculars to the segments AC and BM=DN. Prove that AC bisects BD . Figure

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Fig.4.134,ABC is a right triangle right angled at B and D is the foot of the wedicular dnem from Ben AC. If DM perp BC and DN perp AB, prove that ( i )DM^(2)=DN xx MC( ii) DN^(2)=DM xx AN

In Fig.4.121,ABC is a right triangle right angled at B and D is the foot ot the the perpendicular drawn from B on AC .If DM perp BC and DN perp AB ,prove that: (FIGURE) DM ^(2)=DN xx MC( ii) DN^(2)=DM xx AN