Raoult's Law|Relation Between Mole Fraction In Solution Phase And Vapour Phase|Summary|Questions

Raoult's Law|Relation Between Mole Fraction In Solution Phase And Vapour Phase|Questions|Summary

Vapour Pressure|Factors Affecting Vapour Pressure|Vapour Pressure Of Solutions (Raoult's Law)|Questions|Relation Between Mole Fraction In Solution Phase And Vapour Phase|Summary

Vapour Pressure|Factors Affecting Vapour Pressure|Vapour Pressure Of Solutions (Raoult's Law)|Raoult's Law|Questions|Relation Between Mole Fraction In Solution Phase And Vapour Phase

Vapour Pressure OF Solution and Liquid Composition Curve || Relation between Mole Fraction in Liquid Phase and Vapour Phase || Vapour and Liquid Composition Curve

Camparison between Liquid and Vapour Composition || Determination OF Mole Fraction in Liquid Phase and Vapour Phase || Vapour Pressure OF Different Concentrate/distillate || Solved Numerical Class Question (JH Shortcut)

The vapour pressure of two pure isomeric liquids X and Y are 200 torr and 100 torr respectively at a given temperature. Assuming a solution of these components to obey Raoults law, the mole fraction of component X in vapour phase in equilibrium with the solution containing equal amounts of X and Y, at the same temperature is :

Molality|Relation Between Molarity And Molality|Mole Fraction|Summary

An ideal solution has two components Aand B. If A is more volatile than B and also P_(A)^@ gt P_(T) , then the correct relation between mole fraction of A in liquid (X) and vapour (Y) phase is :

For an ideal biinary liquid solution with p_(A)^(@) gt p_(B)^(@), which is a relationn between X_(A) (mole fraction of A in liquid phase) and Y_(A) (mole fractionn of A in vapour phase) is correct, X_(B) and Y_(B) are mole fractions of B in liquid and vapour phase respectively?