Trigonometry basics class 10 | cbse maths chapter 8 | ncert | important concepts

Trigonometry | Class-9 | CBSE

Class 10 ncert maths solution exercise 8.1 Qn o. 1

Application Of Trigonometry Class 10 | CBSE Class 10 Height And Distance

Most important question class 10 chapter 4 Quadratic equation

Suppose the electron in a hydrogen atom makes transition from n = 3 to n = 2 in 10^(-8)s The order of the torque acting on the electon in this period, using the relation between torque and angular momentum as discussed in the chapter on rotational machanics is

For a general reaction given below, the value of solubility product can be given us {:(A_(x)B_(y),=xA^(+y),+yB^(-x)),(a,0,0),(a-s,xs,ys):} K_(sp)=(xs)^(x).(ys)^(y) (or) K_(sp)=x^(x)y^(y) (S)^(x+y) Solubility product gives us not only an idea about the solubility of an electrolyte in a solvent but also helps in explaining concept of precipitation and calculation [H^(+)] ion, [OH^(-) ] ion. It is also useful in qualitative analysis for the idetification and separation of basic radicals Potussium chromate is slowly aded toa solution containing 0.20M Ag NO_(3) , and 0.20M Ba(NO_(3))_(2) . Describe what happensif the K_(sp) for Ag_(2),CrO_(4) , is 1.1 xx 10^(-12) and the K_(sp) of BaCiO_(4) , is 1.2 xx 10^(-10) ,

For a general reaction given below, the value of solubility product can be given us {:(A_(x)B_(y),=xA^(+y),+yB^(-x)),(a,0,0),(a-s,xs,ys):} K_(sp)=(xs)^(x).(ys)^(y) (or) K_(sp)=x^(x)y^(y) (S)^(x+y) Solubility product gives us not only an idea about the solubility of an electrolyte in a solvent but also helps in explaining concept of precipitation and calculation [H^(+)] ion, [OH^(-) ] ion. It is also useful in qualitative analysis for the identification and separation of basic radicals Potassium chromate is slowly added to a solution containing 0.20M Ag NO_(3) , and 0.20M Ba(NO_(3))_(2) . Describe what happens if the K_(sp) for Ag_(2)CrO_(4) , is 1.1 xx 10^(-12) and the K_(sp) of BaCrO_(4) is 1.2 x 10^(-10) ,