Motion in a Straight Line Class 11th Physics - दूरी विस्थापन | चाल तथा वेग | Ruchi Mam

स्थिति, पथ - लंबाई, विस्थापन |औसत वेग तथा औसत चाल |OMR|Summary

यांत्रिकी (Mechanics)|निर्देश तंत्र (Frame of Reference)|विराम और गति में वस्तुएँ (Objects in Rest and Motion)|बिंदु वस्तु (Point Object)|एकविमीय, द्विविमीय तथा त्रिविमीय गति (Motion in One, Two and Three-Dimensions)|दूरी और विस्थापन (Distance and Displacement)|वेग और चाल (Velocity and Speed)|OMR

Motion & Rest (गति और विरामवस्था)|Distance & Displacement (दूरी और विस्थापन)|Speed & Velocity (चाल और वेग)|OMR|Summary

Motion & Rest (गति और विरामवस्था)|Distance & Displacement (दूरी और विस्थापन)|Speed & Velocity (चाल और वेग)|OMR|Summary

PAIR OF STRAIGHT LINES 11. the equation of one of the line represented ty the eq ial fa) px + qy 0 (b) px-w=0 12. The pair of straight lines passing through th point 1. 2) The pair of straight lines passing through ths point 1. 2)

A particle is moving in a straight line under constant acceleration of 4 m//s^(2) . If its velocity at t=0 is 10 m//s, the displacement of particle in the 5^(th) second of its motion is

The initial velocity of a body moving along a straight lines is 7m//s . It has a uniform acceleration of 4 m//s^(2) the distance covered by the body in the 5^(th) second of its motion is-

Fig. 2 (NCT). 6 shows x-t plot of one dismensional motion a particle. Is it correct to say from the graph that the particle moves in a straight line for t lt 0 and on a parabolic path form t gt 0 ? If not, suggest a suitable physical contxt for this graph.

Position (in m) of a particle moving on a straight line varies with time (in sec) as x=t^(3)//3-3t^(2)+8t+4 (m) . Consider the motion of the particle from t=0 to t=5 sec. S_(1) is the total distance travelled and S_(2) is the distance travelled during retardation. if s_(1)//s_(2)=((3alpha+2))/11 the find alpha .

Motion Under Gravity Explained In Hindi | Explained With Examples | Class 11 Physics