Projectile Motion | समतल मे गति | Physics | 11th | Chapter 4 | Part 3 | Sourabh Sir

Chapter 4 Detailed Explanation Part 3

Chapter 4 Detailed Explanation Part 3

Chapter 4 Detailed Explanation Part 3

A projectile is thrown with a velocity vec v _(0) = 3hati + 4 hatj ms ^(-1) where hat I and hatj are the unit vectors along the horizontal and vertical directions respectively. The speed of the projectile at the highest point of its motion in ms ^(-1) is

Class 12 Physics (Hindi)| Chapter 3 धारा विद्युत् Part 2 | Important Questions | UP Boards

Class 12 Physics (Hindi)| Chapter 3 धारा विद्युत् Part 1| Important Questions | UP Boards

In a projectile motion,the velocity:- (1) is always perpendicular to the acceleration (2) is never perpendicular to the acceleration (3) is perpendicular to the acceleration for one instant only (4) is perpendicular to the acceleration for two instants

A projectile is to be launched from the surface of the earth so as to escape the solar system. Consider the gravitational force on the projectile due to the earth and the sun nly. The projectile is projected perpendicular to the radius vector of the earth relative to the centre of the sun in the direction of motion of the earth. Find the minimum speed of projection relative to the earth so that the projectile escapes out of the solar system. Neglect rotation of the earth. mass if the sum M_(s)2xx10^(30)kg, Mass of the earth M_(e)=6.4xx10^(24)kg Radius if the earth R_(e)=6.4xx10^(6)m, Earth- Sun distence r=1.5xx10^(11)m

Chapter 3 Detailed Explanation Part 4