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There are 5 students in class 10, 6 students in class 11 and 8 students in class 12. If the number of ways, in which 10 students can be selected from them so as to include at least 2 students from each class and at most 5 students from the total 11 students of class 10 and 11 is 100 k, then k is equal to _______.

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If 11 AM's are inserted between 28 and 10, the number of integra AM's is

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Select the related number from the given alternatives : 11 : 1210 :: 10 : ?

In class 12 there are 8 students. In class 11 there are 6 students .In class 10 there are 5 students . Total ways of selecting 10 students , such that there are at least 2 students from each class and at most 5 students from 11 students of Class 10 and 11 combined is 100k. Then find value of k

If 1-5 , 6 -10 , 11-15 , 16-20, ..., are the classes of a frequency distribution , then the lower boundary of the class 11-15 is "_______" .