30 नंबर पक्के✅आज ही करलों सारी रासायनिक अभिक्रियाँ - All Chemical Reaction Chemistry Class 10

9th Chemistry रासायनिक सूत्र कैसे बनाएं ? Chemical Formula Class 9 Tricks | Writing Chemical Formula

Piyush is a student of class 10. His teacher was teaching the type of chemical reactions in the class. Piyush was aksed to carry out the reaction of electrolysis of water in the laboratory. Piyush set up the complete apparatus for the electrolysis of water. He took pure water (distilled water) to carry out this reaction. When Piyush passed electric current through this water for a considerable time even then no chemical reaction took place. Piyush told this problem to his classmate Arjun. Arjun thought over the problem and asked Piyush to add a little of a certain substance into pure water before passing electric current through it. When electric current was passed thorugh water after adding a little of this substance then a chemical reaction took place to form two gases X and Y . The volume of gas X collected over one of the electrodes was 8mL whreas the volume of gas Y collected over the other electrode was 16mL (a) Why no chemical reaction took place when electric current was passed thorugh pure water? (b) What substance was added in little quantity to pure water before passing electric current again? (c) How did the addition of little of this substance help in the electrolysis of water? (d) What is gas X ? Over which electrode is it collected? (e) What is gas Y ? Over which electrode is it collected? (f) What type of chemical reaction is demonstrated by this experiment ? Why? (g) What values are displayed by Arjun in this episode?

The rate constant, the activation energy and the Arrhenius parameter of a chemical reaction at 25^(@)C are 3.0 xx 10^(-4) s^(-1), 104 "kJ mol"^(-1) and 6.0 xx 10^(14)s^(-1) respectively. The value of the rate constant as T rarr oo is

Ravi was performing some experiements related to the laws of chemical combination in the science laboratory under the guidance of his chemistry teacher Mr. John. Ravi found that when he burned 1 gram of hydrogen gas in 8 grams of oxygen gas in a closed vessel, he obtained 9 grams of water. He repeated this experiment many times but obtained the same results every time (a) Write a balanced chemical equation for the reaction between hydrogen and oxygen to form water. Also write the names of all the substances involved below their formulae in the equation (b) What are the reactants and products in the above reaction ? (c) Which law of chemical combination is illustrated by the fact that when Ravi burned 1g of hydrogen in 8g of oxygen, he obtained 9g of water ? (d) What mass of water will be obtained if 1g of hydrogen is burned in 10g of oxygen ? Which law of chemical combination will govern your answer ? (e) What values are displayed by Ravi in this episode ?

We know that balancing of a chemical equation is entirely bases on law of conservation of mass. However the concept of Principle of Atom Conservation (POAC) can also be related to law of consevation of mass in a chemical reaction. So, POAC can also act as a technique for balancing a chemical equation. For example, for a reaction: ABC_(3) rarr AB+C_(2) On applying POAC for A , B and C and related the equations , we get : (n_(ABC_(3)))/(2) =(n_(AB))/(2) =(n_(C_(2)))/(3) ( n_(x) : number of moles of X) Thus , the cofficients of ABC_(3) , AB and C_(2) in the balanced chemical equation will be 2,2 and 3 respectively and the balanced chemical equation can be represented as , 2ABC_(3) rarr 2AB + 3C_(2) If in the above question, the atomic masses of X and Y are 10 and 30 respectively, then the mass of XY_(3) formed when 120 g of Y_(2) reacts completely with X is:

In a college 60 students enrolled in Chemistry,40 in Physics,30 in Biology and 15 in Chemistry and Physics,10 in Physics and Biology and 5 in Biology and Chemistry.No one enrolled in all the three.Find how many are enrolled in at least one of the subjects