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Part 04 Ideal And Nonideal Solution, Cha...

Part 04 Ideal And Nonideal Solution, Chap 02, 12th Chemistry

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Class 12 NEET 2020 - Revision In 60 Days | Aldehyde Ketone and Carboxylic Acid Part 2 | Chemistry

Two liquids A and B have vapour pressure of 0.600 bar and 0.2 bar, respectively. In an ideal solution of the two, calculate the mole fraction of A at which the two liquids have equal partial pressures.

The vapour pressure of a pure liquid A is 70 torr at 300K. It forms an ideal solution with another liquid B. The mole fration of B in the solution is 0.2 and total pressure of solution is 84 torr at 300K. The vapour pressure of pure liquid B at 26^(@)C is

The mole fraction of NaOH in its aqueous solution is 0.2 and density of this solution is 1.12 gm/ml then molarity of the solution is -

Liquid A and B form an ideal solution. The boiling point of solution is 72^(@) C, when the external pressure is 0.6 bar. If then solution contains 200 moles of liquid A, then moles of liquid B is : [Given : P_(A)^(@)=0.4 "bar" "and" P_(B)^(@)=1.0 "bar" "at" 72^(@)C]

NEET 2020 - Revision In 60 Days | Class 12 Solutions | Quick Revision | NEET Chemistry