NCERT 2022 | सरल रेखा में गति - L1 | Motion ​​in a straight line | Hindi Medium | Ravikant Sir | 7PM

The area of a triangle ABC is one unit. DE is a straight line parallel to BC , joining the points D and E on AB and AC respectively such that AD : DB = 1 : 6. The ratio of the areas of the triangles ADE and ABC is : एक त्रिभुज ABC का क्षेत्रफल 1 इकाई है | DE, BC के समानांतर एक सीधी रेखा है जो क्रमशः AB और AC पर स्थित बिंदु D तथा E को इस प्रकार जोड़ती है कि AD : DB = 1 : 6 है | त्रिभुज ADE और ABC के क्षेत्रफल में अनुपात ज्ञात करें |

Consider a plane P passing through A(lambda,3,mu),B(-1,3,2) and C(7,5,10) and a straight line L.with positive direction cosines passing through A,bisecting BC and makes equal angles with the coordinate anes. Let L be a line parallel toL and passing through origin,Which of the following is (are) correct ?

The lens governing the behavior of the rays namely rectilinear propagation laws of reflection and refraction can be summarised in one fundamental law known as Fermat's principle. According to this principle a ray of light travels from one point to another such that the time taken is at a stationary value (maximum or minimum). if c is the velocity of light in a vacuum the velocity in a medium of refractive index mu is (c)/(mu) hence time taken to travel a distance l is (mul)/(c) if the light passes through a number of media, the total time taken is ((1)/(c))summul or (1)/(c)intmudl if refractive index varies continuously. Now summul is the total path, so that fermat's principle states that the path of a ray is such that the optical path in at a stationary value. this principle is obviously in agreement with the fact that the ray are straight lines i a homogenous isotropic medium. it is found that it also agrees with the classical laws of reflection and refraction. Q. If refractive index of a slab varies as mu=1+x^(2) where x is measured from one end then optical path length of a slab of thickness 1 m is

The lens governing the behavior of the rays namely rectilinear propagation laws of reflection and refraction can be summarised in one fundamental law known as Fermat's principle. According to this principle a ray of light travels from one point to another such that the time taken is at a stationary value (maximum or minimum). if c is the velocity of light in a vacuum the velocity in a medium of refractive index mu is (c)/(mu) hence time taken to travel a distance l is (mul)/(c) if the light passes through a number of media, the total time taken is ((1)/(c))summul or (1)/(c)intmudl if refractive index varies continuously. Now summul is the total path, so that fermat's principle states that the path of a ray is such that the optical path in at a stationary value. this principle is obviously in agreement with the fact that the ray are straight lines i a homogenous isotropic medium. it is found that it also agrees with the classical laws of reflection and refraction. Q. The optical path length followed by ray from point A to B given that laws of refraction are obeyed as shown in figure.

The lens governing the behavior of the rays namely rectilinear propagation laws of reflection and refraction can be summarised in one fundamental law known as Fermat's principle. According to this principle a ray of light travels from one point to another such that the time taken is at a stationary value (maximum or minimum). if c is the velocity of light in a vacuum the velocity in a medium of refractive index mu is (c)/(mu) hence time taken to travel a distance l is (mul)/(c) if the light passes through a number of media, the total time taken is ((1)/(c))summul or (1)/(c)intmudl if refractive index varies continuously. Now summul is the total path, so that fermat's principle states that the path of a ray is such that the optical path in at a stationary value. this principle is obviously in agreement with the fact that the ray are straight lines i a homogenous isotropic medium. it is found that it also agrees with the classical laws of reflection and refraction. Q. The optical length followed by ray from point A to B given that laws of reflection are obeyed as shown in figure is

A secondary alkyl halide (A) hydrolyzes with alkali (B) in aqueous medium ismultaneously via S_(N)1 and S_(N)2 pathways with rate constants k_(1) and k_(2) , respectively. form kinetic data, it was found that a plot of = (-1)/([A])(d[A])/(dt) vs [B] is straight line with a slope equal to 2.7 xx 10^(-4) L mol^(-1) min^(-1) and intercept equal to 1.02 xx 10^(-3) . Minimum initial concentration of [A] = 0.2 M and [B] , i.e., [overset(ɵ)(OH)] = 0.5 M . The value of overall rate constant of the hydrolyiss of A (in L mol^(-1) min^(-1)) is