CBSE Class 10 Maths | Arithmetic Progression - L2 | Sum to N Terms of an A.P. | Chapter 5

Class 10 Maths | Chapter 5 | Arithmetic Progression | Important Questions | Quick Revision

If the sum of the first 100 terms of an arithmetic progression is -1 and the sum of the even terms is 1, then the 100^("th") term of the arithmetic progression is

Let S_1 be the sum of first 2n terms of an arithmetic progression. Let S_2 be the sum first 4n terms of the same arithmeti progression. If (S_(2)-S_(1)) is 1000, then the sum of the first 6n term of the arithmetic progression is equal to :

If T_(54) is an fifty fourth term of an Arithmetic Progression is -61 and T_(4) is fourth term of an same Arithmetic progression is 64, then T_(10) of that series will be ( T_(n) = n^("th ") term of an A.P.)

Arithmetic Progression(A.P) | Arithmetic progression problems

Arithmetic Progression(A.P) | Arithmetic progression problems

Let fourth therm of an arithmetic progression be 6 and m^(th) term be 18. If A.P has intergal terms only then the numbers of such A.P s is "____________"

The sum of the first n-terms of the arithmetic progression is equal to half the sum of the next n terms of the same progression.Find the ratio of the sum of the first 3n terms of the progressionto the sum of its first n-terms.

If S_(n) denotes the sum of first n terms of an arithmetic progression and an denotes the n^(th) term of the same A.P.given S_(n)=n^(2)p; where p,n in N, then

Suppose the sum of the first m teams of a arithmetic progression is n and the sum of its first n terms is m, where mnen. Then the dum of the first (m + n) terms of the arithmetic progression is