L 02 कोलाईडी विलयन एवं गुण Colliodal Solution || Chap 05 || 12th NEET & IIT JEE

12.825 gm of a sample of Ba(OH)_(2) is dissolved in 10 ml of 0.5 N HCl solution. The excess of HCl was titrated with 0.2 N NaOH . The volume of NaOH used was 10 c c . The percentage of Ba(OH)_(2) in the sample is

Two solutions of HCl, A and B have concentration of 0.5 N and 0.1 M respectively . The volume of solutions A and B required to make 2 L of 0.2 N HCl are

The volumes of two HCl solution A (0.5 M) and B (0.1M) to be mixed for preparing 2 L of 0.2 M HCl are

Assuming no change in volume , the time required to obtain solution of ph = 12 by electrolysis of 50 mL 0.1 M NaCl (using current of 0.5 amp) will be

A mmonia is highly soluble gas in water and gives a alkaline solution of NH_(4) OH . What volume of NH_(3) gas at STP will be required to the passed in 100 mL of 0.5 M H_(2) SO_(4) to bring down its strength to 0.25 M ? (For titrations with aqueous NH_(3) , it is assumed that NH_(4) OH dissociates to 100% extent) a. 2.24 L b. 1.68 L c. 1.12 L d. 0.56 L

Objective question (single correct answer). i. H_(3) PO_(4) is a tribasic acid and one of its salt is NaH_(2) PO_(4) . What volume of 1M NaOH solution should be added to 12 g of NaH_(2) PO_(4) to convert in into Na_(3) PO_(4) ? a. 100 mL b. 2 mol of Ca (OH)_(2) c. Both d. None iii. The normality of a mixture obtained mixing 100 mL of 0.2 m H_(2) SO_(4) with 100 mL of 0.2 M NaOH is: a. 0.05 N b. 0.1 N c. 0.15 N d. 0.2 N iv 100 mL solution of 0.1 N HCl was titrated with 0.2 N NaOH solutions. The titration was discontinued after adding 30 mL of NaOH solution. The reamining titration was completed by adding 0.25 N KOH solution. The volume of KOH required from completing the titration is: a. 70 mL b. 35 mL c. 32 mL d. 16 mL