NCERT 2022 | सारणिक - L1 | determinant | Class 12 गणित | Hindi Medium | Jitendra Sir | 8 AM |

Class 11 के बाद क्या ? Class 12 Hindi Medium की पढ़ाई साल के शुरू से कैसे करें ?

NEET 2020 - Revision In 60 Days | NCERT Class 12 Principle of Inheritance and Variation Part -1 | NEET Biology

Class 12 Maths | Chapter 4 | Determinants | Important Questions | Quick Revision| Part 1

NEET 2020 - Revision In 60 Days | NCERT Class 12 Molecular Basis of Inheritance Part -1 | NEET Biology

NEET 2020 - Revision In 30 Days | NCERT Class 12 Chapter 1 Reproduction In Organisms - Quick Revision | NEET Biology

For the following reaction, the rate law has been determined to be Rate = k[A][B]^2" with " k = 2.0 xx 10^(-6) mol^(-2) L^(2)s^(-1) 2A + B C to A_2B + C For this reaction determine the initial rate of the reaction with [A] = 0.1 mol L^(-1) , [B] = 0.2 mol L^(-1) ,[C] = 0.8 mol L^(-1)

Class 12 Maths (Hindi) | Chapter 4 सारणिक | Important Questions | Quick Revision | Part-1

A certain gas occupies a volume of 0.76 L at a pressure of 1.2 atm and a temperature of 4000 K. It is expanded adiabatically to a volume of 4.3 L. Determine (a) the final pressure and (b) the final temperature, assuming the gas to be an ideal gas for which gamma = 1.4.

JEE Mains & Advanced | Chemistry - Ideal Gases By Vipin Sir | L1 English Medium

For the following reaction: 2A + B +C rarr A_(2)B + C The rate law has been determined to be Rate = k[A][B]^(2) with k = 2.0 xx 10^(-6) mol^(-2) L^(2) s^(-1) For this reaction, determine the initial rate of the reaction with [A] = 0.1 mol L^(-1), [B] = 0.2 mol L^(-1), C = 0.8 mo, L^(-1) . Determine the rate after 0.04 mol L^(-1) of A has reacted.