जैव -विविधता एवं संरक्षण | Class12 NCERT जीव विज्ञान | 2 PM Class By Dr. Priyanka Ma'am |L5 |

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Arrange the following activities in a logical and meaningful order. निम्नलिखित गतिविधियों को एक तर्कपूर्ण और अर्थपूर्ण क्रम में व्यवस्थित करें | 1. Attending classes in college /कॉलेज में कक्षाओं में शामिल होना 2. Admission merit list declaration /नामांकन की मेरिट सूची की घोषणा 3. Getting admission in the college /कॉलेज में नामांकन लेना 4. Applying for admission to college /कॉलेज में नामांकन के लिए आवेदन देना 5. Annual Examination – Class 12 /वार्षिक परीक्षा - कक्षा 12 6. Result declaration – Class 12 /परिणाम की घोषणा - कक्षा 12

In class 12 there are 8 students. In class 11 there are 6 students .In class 10 there are 5 students . Total ways of selecting 10 students , such that there are at least 2 students from each class and at most 5 students from 11 students of Class 10 and 11 combined is 100k. Then find value of k

Complete the following activity by filing the boxes : Here, L = 90, N/2 = 45, cf = 30, f = 25 , h = class interval of the median class = square Median = L + [(N/2 - cf)/f] xx h …(Formula) = square+ (square-square)/25 xx 5 .....(Substituting the values) = square + square/5 = square + square = 93

In a frequency distribution table with 12 classes, the class-width is 2.5 and the lowest class boundary is 8.1, then what is the upper class boundary of the highest class?

If in a frequency distribution table with 12 classes, the width of each class is 2.5 and the lowest class boundary is 6.1, then what is the upper class boundary of the highest class ?

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