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NEET 2022 | सरल रेखा में गति - L11 |Moti...

NEET 2022 | सरल रेखा में गति - L11 |Motion ​​in a straight line | Hindi Medium | Ravikant Sir | 4 PM

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Position (in m) of a particle moving on a straight line varies with time (in sec) as x=t^(3)//3-3t^(2)+8t+4 (m) . Consider the motion of the particle from t=0 to t=5 sec. S_(1) is the total distance travelled and S_(2) is the distance travelled during retardation. if s_(1)//s_(2)=((3alpha+2))/11 the find alpha .

STATEMENT-1: Let DeltaABC be rigtht angle with vertices A(0,2),B(1,0)and C(0,0) if D is the point on AB such that the segment CD bisects angle C then the length of CD is (2sqrt2)/(3). STATEMENT-2: The number of points on the straight line which joins (-4,11) to (16,-1) whose co-ordinates are positve interger is 3. STATEMENT-3: If k=2 then the lines L_(1):2x+y-3=0,L_(2):5x+ky-3=0and L_(3):3x-y-2=0 are concurrent.

A secondary alkyl halide (A) hydrolyzes with alkali (B) in aqueous medium ismultaneously via S_(N)1 and S_(N)2 pathways with rate constants k_(1) and k_(2) , respectively. form kinetic data, it was found that a plot of = (-1)/([A])(d[A])/(dt) vs [B] is straight line with a slope equal to 2.7 xx 10^(-4) L mol^(-1) min^(-1) and intercept equal to 1.02 xx 10^(-3) . Minimum initial concentration of [A] = 0.2 M and [B] , i.e., [overset(ɵ)(OH)] = 0.5 M . The value of overall rate constant of the hydrolyiss of A (in L mol^(-1) min^(-1)) is

A secondary alkyl halide (A) hydrolyzes with alkali (B) in aqueous medium ismultaneously via S_(N)1 and S_(N)2 pathways with rate constants k_(1) and k_(2) , respectively. form kinetic data, it was found that a plot of = (-1)/([A])(d[A])/(dt) vs [B] is straight line with a slope equal to 2.7 xx 10^(-4) L mol^(-1) min^(-1) and intercept equal to 1.02 xx 10^(-3) . Minimum initial concentration of [A] = 0.2 M and [B] , i.e., [overset(ɵ)(OH)] = 0.5 M . The initial rate of consumption is isopropyl chloride (in M min^(-1)) is

In triangle ABC a straight line parallel to BC intersects AB and AC at D and E respectively. If AB = 2AD, then DE : BC is - त्रिभुज ABC में BC के समांतर एक सरल रेखा AB और AC को क्रमशः D और E पर काटती है । यदि AB= 2AD, तो DE : BC कितना होगा ।