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किशोरावस्था की ओर | CLASS 8 विज्ञान | 5 ...

किशोरावस्था की ओर | CLASS 8 विज्ञान | 5 PM Class by Nishtha ma'am | L2 | Hindi Medium

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Class 11 के बाद क्या ? Class 12 Hindi Medium की पढ़ाई साल के शुरू से कैसे करें ?

Complete the following activity by filing the boxes : Here, L = 90, N/2 = 45, cf = 30, f = 25 , h = class interval of the median class = square Median = L + [(N/2 - cf)/f] xx h …(Formula) = square+ (square-square)/25 xx 5 .....(Substituting the values) = square + square/5 = square + square = 93

The probability that a student selected at random from a class will pass in Hindi is 4/5 and the probability that he passes in Hindi and English is 1/2 . What is the probability that he will pass in English if it is known that he has passed in Hindi ?

There are five classes: class 1, class 2, class 3, class 4 and class 5 in a school. They are one above the other. Class 1 is at the bottom, then class 2 above it and so on. Five videos M1, M2, M3, M4 and M5 are displayed in these given classes. Only one video is displayed in a particular class. Each video is displayed only one time. Video M5 is displayed at a even numbered class. Video M2 is displayed at class 1. Video M1 is displayed at the class just below M5. Video M4 is not displayed at even numbered class. एक स्कूल में पाँच कक्षाएं हैं: कक्षा 1, कक्षा 2, कक्षा 3, कक्षा 4 और कक्षा 5। वे एक के ऊपर एक हैं। कक्षा | सबसे नीचे है, फिर कक्षा 2 इसके ऊपर और इसी तरह ऊपर। इन दिए गए वर्गों में पांच वीडियो M 1, M 2, M 3, M 4 और M 5 प्रदर्शित किए गए हैं। केवल एक वीडियो एक विशेष वर्ग में प्रदर्शित होता है। प्रत्येक वीडियो को केवल एक बार प्रदर्शित किया जाता है। वीडियो M5 को एक सम संख्या वाले वर्ग में प्रदर्शित किया जाता है। वीडियो M2 को कक्षा 1 में प्रदर्शित किया गया है। वीडियो M1 को M5 के ठीक नीचे की कक्षा में प्रदर्शित किया गया है। वीडियो M4 को किसी भी सम संख्या वाले में प्रदर्शित नहीं किया गया है। Which of the following statement is not correct? / निम्नलिखित में से कौन सा कथन सही नहीं है?

12 PM Special Class | Class 11 - STRUCTURE OF ATOM || BOHR MODEL By Yakshu Ma'am

In class 12 there are 8 students. In class 11 there are 6 students .In class 10 there are 5 students . Total ways of selecting 10 students , such that there are at least 2 students from each class and at most 5 students from 11 students of Class 10 and 11 combined is 100k. Then find value of k

There are 5 brilliant students in class XI and 8 brilliant students in class XlIl.Each class has 50 students.The odds in favour of choosing the class XI are 2:3. One of the classes is chosen randomly and then a student is randomly selected.Find the probability of selecting a brilliant student.

Thirty children were asked about the number of hours they watched TV programmes in the previous week. The results were found as follows: 1 6 2 3 5 12 5 8 4 8 10 3 4 12 2 8 15 1 17 6 3 2 8 5 9 6 8 7 14 12 (i) Make a grouped frequency distribution table for this data, taking class width 5 and one of the class intervals as 5 - 10. (ii) How many children watched television for 15 or more hours a week?

In a class of 50 students, 23 speak English, 15 speak Hindi and 18 speak Punjabi. 3 speak only English and Hindi, 6 speak only Hindi and Punjabi and 6 speak only English and Punjabi. If 9 speak only English, then how many speak all the three? (a) 1 (b) 2 (c) 3 (d) 5

In a frequency distribution table with 12 classes, the class-width is 2.5 and the lowest class boundary is 8.1, then what is the upper class boundary of the highest class?