NCERT 2022 | रेखाएँ एवं कोण - L6 | lines and angles | Class 9 गणित | Hindi Medium | Amit Sir | 6 PM

For the straight line 4x + 3y - 6 = 0 and 5x + 12y + 9 = 0 , find the equation of the bisector of the obtuse angle between them.

Show that the equation x^(2)-6xy+5y^(2)+10x-14y+9=0 represents a pair of lines. Find the acute angle between them. Also find the point of intersection of the lines.

The given pie Chart (angles are not as per chosen scale) presents the marks scored by Amit in five subjects. Maximum marks in each subject = 100 Total score of Amit = 450 दिया गया वृत्त-आरेख ( कोण किसी चयनित पैमाने के अनुसार नहीं हैं ) पांच विषयों में अमित के द्वारा प्राप्त किये गए अंकों को दर्शाता है | प्रत्येक विषय के अधिकतम अंक = 100 अमित का कुल प्राप्तांक =450 What is the difference between the marks scored by Amit in Hindi and Maths? अमित के द्वारा हिंदी और गणित में प्राप्त किये गए अंकों में क्या अंतर है?

In angle PQR,PQ =6 cm , PR =9cm and M is a point on QR such that it divides QR in the ratio 1: 2 PM bot QR . Find QR.

In the given figure l and m are parallel lines and t is a transversal such that angle1=135^(@) find the measure of each one of the angels angle2,angle3,angle4,angle5,angle6,angle7. AND angle8

In the figure, line AB||line CD|| line EF, line l and line m are its transversals. If AC = 6, CE = 9, BD = 8 then complete the following activity to find DF. Activity : line AB|| line CD|| line EF and line l and m are the transversals. (AC)/(square) = (square)/(DF) ..[Property of three parallel lines and their transversals] :. (6)/(9) = (square)/(DF) DF = square

The d.r.'s of the line AB are (6,-2,9) . If the line AB makes angles alpha,beta with OY, OZ respectively where O=(0,0,0) then sin^(2)alpha-sin^(2)beta= .....

If the tangent to the curve y= (x)/(x^(2) - 3), x in r ( xne pm sqrt3) , at a point (alpha, beta ) ne (0, 0) on it is parallel to the line 2x + 6y -11 =0 , then (A) |6alpha + 2beta|=19 (B) |6alpha + 2 beta|=9 (C) |2 alpha + 6 beta |= 19 (D) | 2 alpha + 6 beta| = 11