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परासरण दाब Osmotic Pressure विलयन Soluti...

परासरण दाब Osmotic Pressure विलयन Solution Ch1 Lec 7 || 12th Chemistry By Poonam Ma'am

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If the observed and normal osmotic pressure of 1% NaCl solution are 5.7 and 3.0 atm, the degree of dissociation of NaCl is :

Given : 1 L, 2M solution of C_(12)H_(22)O_(11) under go first order reaction. C_(12)H_(22)O_(11)+H_(2)Orarr C_(6)H_(12)O_(6)+C_(6)H_(12)O_(6) {:(,"Angle of rotation ",theta,20^(@),-10^(@),-40^(@)),(,"Time",t("min"),0,10,oo):} If osmotic pressure of solution is pi atm at (300)/(0.821)K temperature after 10 min then calculate the value of (pi)/(10) ?

Two solutions of glucose have osmotic pressure 1.5 and 2.5 atm ,respectively. 1 L of first solution is mixed with 2 L of second solution. The osmotic pressure of the resultant solution will be a. 2.62 atm , b. 6.12 atm ,c. 3.26 atm , d. 2.16 atm

pH of 0.1M solution HCl is changed by 0.3 unit due dilution, calculate change in osmotic pressure if temperature of solution is 300K. (R = 1//12" " "litre atm"//K//"mole")