प्रकाश - परावर्तन तथा अपवर्तन | Class - 10 विज्ञान | 5 PM Class by Amba Ma'am | L2 | Hindi Medium

12 PM Special Class | Class 11 - STRUCTURE OF ATOM || BOHR MODEL By Yakshu Ma'am

Class 10 Science | Chapter 5 Periodic Classification of Elements | Important Questions and Quick Revision| Part 2

The probability that a student selected at random from a class will pass in Hindi is 4/5 and the probability that he passes in Hindi and English is 1/2 . What is the probability that he will pass in English if it is known that he has passed in Hindi ?

In class 12 there are 8 students. In class 11 there are 6 students .In class 10 there are 5 students . Total ways of selecting 10 students , such that there are at least 2 students from each class and at most 5 students from 11 students of Class 10 and 11 combined is 100k. Then find value of k

study the following information carefully and answer the questions given below it. An exhibition is open for pubic since 9 am till 3 pm and again since 4 pm till 10 pm in a day. There are 12 batches of 1 hour each. The entry ticket bears a pass code made up of seven words, which changes every hour following a particular rule. The pass codes for 4 pm to 10 pm are same as those for respective hours during 9 am to 3 pm i.e., the pass code for 4 pm to 5 pm is same as that of 9 am to 10 am and so on. Following is an illustration of the code and steps of rearrangement for subsequent clock hours. First batch : 9 am to 10 am (4 pm to 5 pm) Pass code : dig more and you will find water Second batch : 10 am to 11 am (5 pm to 6 pm) Pass code : and dig find you water will more Third batch : 11 am to 12 noon (6 pm to 7 pm) Pass code : find and will you more water dig and so on. If the pass code for 5 pm to 6 pm is 'out in above over the field end', what will be the pass code for 1 pm to 2 pm ?

There are 5 students in class 10, 6 students in class 11 and 8 students in class 12. If the number of ways, in which 10 students can be selected from them so as to include at least 2 students from each class and at most 5 students from the total 11 students of class 10 and 11 is 100 k, then k is equal to _______.