NCERT 2022 | विद्युत - L4 | Electricity | Class 10 विज्ञान | Hindi Medium | Ruchi Ma'am| 6 PM

The cube shown in Fig. 2.119 has sides of length L = 10.0 cm . The electric field is uniform , has a magnitude E = 4.00 xx 10^(3) NC^(-1) and is parallel to the xy plane at an angle of 37^(@) measured from the + x - axis toward the + y - axis . Electric flux passing through surface S_(6) is

A uniform electric field E=91xx10^(-6) V//m is created between two parallel, charged plates as shown in figure. An electron enters the field symmetrically between the plates with a speed v_(0)=4xx10^(3) m//s . The length of each plates is l=1m . Find the angle of deviation of the path of the electron as it comes out of the field. (Mass of the electron is m=9.1xx10^(-31) kg and its charge is e=-1.6xx10^(-19) C ).

Figure shows an assembly of deflecting plates A and B ofan ink-jet printer which causes moving ink droplets to deflect at desired displacements by continuously varying electric field between the plates. An ink drop with a mass m = 1.3 xx 10^(-10)kg and a negative charge of magnitude q = 1.5x x 10^(-13)C enters the region between the plates, initially moving along the x-axis with speed v_(x), = 18m//s . The length of plates is L = 1.6cm . The plates are connected with a varying voltage and thus produce an electric field at all points between them. Assume that field vec(E) for some duration is constant and it is acting in downward direction as shown and has a magnitude of E = I .4 xx 10^(6) N//C , find the vertical deflection of the drop at the far edge ofthe plate? As the gravitational force on the drop is very small relative to the electrostatic force acting on the drop, it can be neglected for this analysis. [6.4 xx 10^(-4)m]

A capacitor of capacitance C=15pF is charged with voltage V=500V . The electric field inside the capacitor with dielectric is 10^(6)V//m and the area of the plate 10^(-4)m^(2) , then the dielectric constant of the medium is : (._(epsilon0)=8.85xx10^(-12) in S.I units) (A) 12.47 (B) 8.47 (C) 10.85 (D) 14.85

Polonium ( _84^210 Po ) emits _2^4He particles and is converted into lead ( _82^206Pb ). This reaction is used for producing electric power in a space mission. Po^210 has half-life of 138.6 days. Assuming an efficiency of 10% for the thermoelectric machine, how much ^210Po is required to produce 1.2xx10^7J of electric energy per day at the end of 693 days. Also find the initial activity of the material. Given : Masses of nuclei ^210Po=209.98264 amu, ^206Pb=205.97440 amu, _2^4He=4.00260 amu, 1 am u=931 MeV//c^2 and Avogadro's number = 6xx10^23//mol