परिमेय संख्याएँ | CLASS 8 - गणित | 6 PM Class by Manik Sir | L2 | Hindi Medium

JEE Mains & Advanced | Chemistry - Ideal Gases By Vipin Sir | L2 English Medium

Acids,Bases and pH - Class 10 Science | 7 PM Master Class By Vipin Sir

Problems Based on class 1, 2, 3, 4, 5 and 6

Class 11 के बाद क्या ? Class 12 Hindi Medium की पढ़ाई साल के शुरू से कैसे करें ?

Class 10 Maths (Hindi) | Chapter 8 | त्रिकोणमिति का परिचय | Important Questions and Quick Revision

In class 12 there are 8 students. In class 11 there are 6 students .In class 10 there are 5 students . Total ways of selecting 10 students , such that there are at least 2 students from each class and at most 5 students from 11 students of Class 10 and 11 combined is 100k. Then find value of k

If in a frequency distribution table with 12 classes, the width of each class is 2.5 and the lowest class boundary is 6.1, then what is the upper class boundary of the highest class ?

The probability that a student selected at random from a class will pass in Hindi is 4/5 and the probability that he passes in Hindi and English is 1/2 . What is the probability that he will pass in English if it is known that he has passed in Hindi ?

The width of each of nine classes in a frequency distribution is 2.5 and the lower class boundary of the lowest class 10.6. Then the upper class boundary of the highest class is 35.6 (b) 33.1 (c) 30.6 (d) 28.1