Home
Class
CHEMISTRY
हैलोऐल्केन तथा हैलोऐरीन | Class 12 NCERT...

हैलोऐल्केन तथा हैलोऐरीन | Class 12 NCERT रसायन विज्ञान | 8 PM Class By Ram Sir | L2 | Hindi Medium

Promotional Banner

Similar Questions

Explore conceptually related problems

Class 11 के बाद क्या ? Class 12 Hindi Medium की पढ़ाई साल के शुरू से कैसे करें ?

NEET 2020 - Revision In 60 Days | NCERT Class 12 Molecular Basis of Inheritance Part -2 | NEET Biology

NEET 2020 - Revision In 30 Days | NCERT Class 12 Chapter 2 Sexual Reproduction In Flowering Plants | NEET Biology Revision

Class 12 Physics (Hindi)| Chapter 3 धारा विद्युत् Part 2 | Important Questions | UP Boards

NEET 2020 - Revision In 60 Days | NCERT Class 12 Principle of Inheritance and Variation Part -2 | NEET Biology

Class 12 Biology | Chapter 8 | Human Health and Disease | Important Questions and Quick Revision | Part 2

In a frequency distribution table with 12 classes, the class-width is 2.5 and the lowest class boundary is 8.1, then what is the upper class boundary of the highest class?

In class 12 there are 8 students. In class 11 there are 6 students .In class 10 there are 5 students . Total ways of selecting 10 students , such that there are at least 2 students from each class and at most 5 students from 11 students of Class 10 and 11 combined is 100k. Then find value of k

There are 5 students in class 10, 6 students in class 11 and 8 students in class 12. If the number of ways, in which 10 students can be selected from them so as to include at least 2 students from each class and at most 5 students from the total 11 students of class 10 and 11 is 100 k, then k is equal to _______.

Thirty children were asked about the number of hours they watched TV programmes in the previous week. The results were found as follows: 1 6 2 3 5 12 5 8 4 8 10 3 4 12 2 8 15 1 17 6 3 2 8 5 9 6 8 7 14 12 (i) Make a grouped frequency distribution table for this data, taking class width 5 and one of the class intervals as 5 - 10. (ii) How many children watched television for 15 or more hours a week?