NEET 2022 | सरल रेखा में गति - L8 | Motion ​​in a straight line | Hindi Medium | Ravikant Sir | 4 PM

he straight line L is perpendicular to the line 4x-y=1. The area of the triangle formed by the line L and the coordinate axis is 8. Then the equation of the straight line with positive intercept on y-axis,is

Position (in m) of a particle moving on a straight line varies with time (in sec) as x=t^(3)//3-3t^(2)+8t+4 (m) . Consider the motion of the particle from t=0 to t=5 sec. S_(1) is the total distance travelled and S_(2) is the distance travelled during retardation. if s_(1)//s_(2)=((3alpha+2))/11 the find alpha .

The angular momentum of a particle about origin is varying as L =4t+8(SI units) whern its moves along a straight line y=x-4(x,y in metres). The magnitude of force acting on the particle will be

A secondary alkyl halide (A) hydrolyzes with alkali (B) in aqueous medium ismultaneously via S_(N)1 and S_(N)2 pathways with rate constants k_(1) and k_(2) , respectively. form kinetic data, it was found that a plot of = (-1)/([A])(d[A])/(dt) vs [B] is straight line with a slope equal to 2.7 xx 10^(-4) L mol^(-1) min^(-1) and intercept equal to 1.02 xx 10^(-3) . Minimum initial concentration of [A] = 0.2 M and [B] , i.e., [overset(ɵ)(OH)] = 0.5 M . The value of overall rate constant of the hydrolyiss of A (in L mol^(-1) min^(-1)) is

A secondary alkyl halide (A) hydrolyzes with alkali (B) in aqueous medium ismultaneously via S_(N)1 and S_(N)2 pathways with rate constants k_(1) and k_(2) , respectively. form kinetic data, it was found that a plot of = (-1)/([A])(d[A])/(dt) vs [B] is straight line with a slope equal to 2.7 xx 10^(-4) L mol^(-1) min^(-1) and intercept equal to 1.02 xx 10^(-3) . Minimum initial concentration of [A] = 0.2 M and [B] , i.e., [overset(ɵ)(OH)] = 0.5 M . The initial rate of consumption is isopropyl chloride (in M min^(-1)) is

Let L_1 be a tangent to the parabola y^(2) = 4(x+1) and L_2 be a tangent to the parabola y^(2) = 8(x+2) such that L_1 and L_2 intersect at right angles. Then L_1 and L_2 meet on the straight line :

A straight line L is perpendicular to the line 4x-2y=1 and forms a triangle of area 4 sq.units with coordinate axes then, the equation of L is (i) 2x+4y+8=0 (ii) 2x-4y+8=0 (iii) 2x+4y+7=0 (iv) 4x-2y-7=0