NOUNS | Introduction to Nouns & Its Types |English Grammar |3PM Class By Manisha Ma'am |L1| Doubtnut

If the first half of English alphabet is reversed and the second half of the English alphabet, is left undisturbed then answer the question given below. A B C D E F G H I J K L M N O P Q R S T U V W X Y Z Which letter of the first half does not change its position when 1st half of the English alphabet is reversed? 1) F 2) G 3) T 4) S 5) None of these

Study the following information carefully and answer the questions given below. There are five vehicles of different types viz., Bus, Van, Bike, Truck and Jeep in a garage but not necessarily in the same order. They are serviced at different timing in a single day. The duration of their servicing in the garage may or may not be different. The total duration of the servicing in the garage by the mechanic is of 11 hours. There is no gap between the servicing time of all vehicles. The duration of servicing is either a full hour or half an hour but not in one third or one fourth. The van was serviced in the garage from 12:30 pm to 3 pm. Jeep was taken for servicing immediately after the Van. The servicing hour of Jeep in the garage is three hours. The duration of servicing of Truck is more than the duration of servicing of Bike in the garage by 1 hour. Truck was serviced just after the servicing of Bike. The truck was not serviced at the last. The bus was serviced in the garage before Van but not immediately before. The duration of servicing of the bus is of 1.5 hours. The servicing of the bike is after 6:00 am. Which among the following was serviced from 3:00-6:00 pm?

It is tempting to think that all possible transitions are permissible, and that an atomic spectrum arises from the transition of an electron from nay initial orbital to any other orbital. However, this is no so, because a photon has an intrinsic spin angular momentum of sqrt(2)(h)/(2pi) corresponding to S = 1 although it has no charge and no rest mass. on the otherhand, an electron has got two types of angular momentum: Orbital angular momentum, L = = sqrt(l(l+1))(h)/(2pi) and spin angular momentum, L_(s) (=sqrt(s(s+1))(h)/(2pi)) arising from orbital motion and spin motion of electron respectively. The change in angular momentum of the electron during any electronic transition must compensate for the angular momentum carried away by the photon. To satisfy this condition the difference between the azimuthal quantum numbers of the orbitals within which transition takes place must differ by one. Thus, an electron in a d-orbital (l=2) cannot make a transition into an s-orbital (l=0) because the photon cannot carry away enough angular momentum. An electron, possess four quantum numbers, n l, m and s. Out of these four l determines the magnitude of orbital angular momentum (mentioned above) while m determines its Z-component as m((h)/(2pi)) . The permissible values of only integers right from -l to +l . While those for l are also integers starting from 0 to (n-1) . The values of l denotes the sub-shell. For l = 0,1,2,3,4... the sub-shells are denoted by the symbols s,p,d,f,g....respectively. The maximum orbital angular momentum of an electron with n = 4 is

It is tempting to think that all possible transitions are permissible, and that an atomic spectrum arises from the transition of an electron from nay initial orbital to any other orbital. However, this is no so, because a photon has an intrinsic spin angular momentum of sqrt(2)(h)/(2pi) corresponding to S = 1 although it has no charge and no rest mass. on the otherhand, an electron has got two types of angular momentum: Orbital angular momentum, L = = sqrt(l(l+1))(h)/(2pi) and spin angular momentum, L_(s) (=sqrt(s(s+1))(h)/(2pi)) arising from orbital motion and spin motion of electron respectively. The change in angular momentum of the electron during any electronic transition must compensate for the angular momentum carried away by the photon. To satisfy this condition the difference between the azimuthal quantum numbers of the orbitals within which transition takes place must differ by one. Thus, an electron in a d-orbital (l=2) cannot make a transition into an s-orbital (l=0) because the photon cannot carry away enough angular momentum. An electron, possess four quantum numbers, n l, m and s. Out of these four l determines the magnitude of orbital angular momentum (mentioned above) while m determines its Z-component as m((h)/(2pi)) . The permissible values of only integers right from -l to +l . While those for l are also integers starting from 0 to (n-1) . The values of l denotes the sub-shell. For l = 0,1,2,3,4... the sub-shells are denoted by the symbols s,p,d,f,g....respectively. The orbital angular momentum of an electron in p-orbital makes an angle of 45^(@) from Z-axis. Hence Z-component of orbital angular momentum of electron is:

It is tempting to think that all possible transitions are permissible, and that an atomic spectrum arises from the transition of an electron from nay initial orbital to any other orbital. However, this is no so, because a photon has an intrinsic spin angular momentum of sqrt(2)(h)/(2pi) corresponding to S = 1 although it has no charge and no rest mass. on the otherhand, an electron has got two types of angular momentum: Orbital angular momentum, L = = sqrt(l(l+1))(h)/(2pi) and spin angular momentum, L_(s) (=sqrt(s(s+1))(h)/(2pi)) arising from orbital motion and spin motion of electron respectively. The change in angular momentum of the electron during any electronic transition must compensate for the angular momentum carried away by the photon. To satisfy this condition the difference between the azimuthal quantum numbers of the orbitals within which transition takes place must differ by one. Thus, an electron in a d-orbital (l=2) cannot make a transition into an s-orbital (l=0) because the photon cannot carry away enough angular momentum. An electron, possess four quantum numbers, n l, m and s. Out of these four l determines the magnitude of orbital angular momentum (mentioned above) while m determines its Z-component as m((h)/(2pi)) . The permissible values of only integers right from -l to +l . While those for l are also integers starting from 0 to (n-1) . The values of l denotes the sub-shell. For l = 0,1,2,3,4... the sub-shells are denoted by the symbols s,p,d,f,g....respectively. The spin-only magnetic moment of a free ion is sqrt(8)B.M . The spin angular momentum of electron will be

Study the following information carefully and answer the questions given below. There are five vehicles of different types viz., Bus, Van, Bike, Truck and Jeep in a garage but not necessarily in the same order. They are serviced at different timing in a single day. The duration of their servicing in the garage may or may not be different. The total duration of the servicing in the garage by the mechanic is of 11 hours. There is no gap between the servicing time of all vehicles. The duration of servicing is either a full hour or half an hour but not in one third or one fourth. The van was serviced in the garage from 12:30 pm to 3 pm. Jeep was taken for servicing immediately after the Van. The servicing hour of Jeep in the garage is three hours. The duration of servicing of Truck is more than the duration of servicing of Bike in the garage by 1 hour. Truck was serviced just after the servicing of Bike. The truck was not serviced at the last. The bus was serviced in the garage before Van but not immediately before. The duration of servicing of the bus is of 1.5 hours. The servicing of the bike is after 6:00 am. Which among the following was serviced just after bus?

Study the following information carefully and answer the questions given below. There are five vehicles of different types viz., Bus, Van, Bike, Truck and Jeep in a garage but not necessarily in the same order. They are serviced at different timing in a single day. The duration of their servicing in the garage may or may not be different. The total duration of the servicing in the garage by the mechanic is of 11 hours. There is no gap between the servicing time of all vehicles. The duration of servicing is either a full hour or half an hour but not in one third or one fourth. The van was serviced in the garage from 12:30 pm to 3 pm. Jeep was taken for servicing immediately after the Van. The servicing hour of Jeep in the garage is three hours. The duration of servicing of Truck is more than the duration of servicing of Bike in the garage by 1 hour. Truck was serviced just after the servicing of Bike. The truck was not serviced at the last. The bus was serviced in the garage before Van but not immediately before. The duration of servicing of the bus is of 1.5 hours. The servicing of the bike is after 6:00 am. What is the duration (in hours) of the Bike’s servicing?

Study the following information carefully and answer the given questions based on it The English alphabet is categorised into five groups, each starting with a vowel and encompassing the immediately following consonants in the group. Thus group one consists of A, B, C and D, group two consists of E, F,G and H, group three consists of 1, J, K, L, M and N, group four consists of O, P, Q,R, S and T, and the remaining letters make group five. These groups are assigned values as 10 for each letter of first group, 20 for each letter of second group, 30 for each letter of third group, 40 for each letter of fourth group, and 50 for each letter of group five. When used to form words, the value of each letter should be added up to compute the value of the word. If the word has letters only from the same group the value of the word would be the value of the sum of letters. However, if the letters in a word are from difierent groups, the value of the first letter of the word and any other letter of that group will be the same as that of its individual letter value of its group, but that of a letter from another group will be 'double’ as much as the value of each letter of its group. If we have to find the value of MANGO, its first letter is M (from third group), among A, N, G and O, N is also from third group. Hence value of M + N = 30 + 30 = 60 Now A, G and O belong to first, second and the fourth group respectively. Hence value of A + G + O = double the value of A + double the value of G + double the value of O = 2*10 + 2*20 + 2* 40 = 140. Hence, total value = 140+600 = 200.which one or two or three of the words denoted by A, B and C correspond to the given value. 220 (A)THEY (B)EASY (C)VALUE 1) A and B only 2) B and C only 3) A and C only 4) All the three 5) None of these

Study the following information carefully and answer the given questions based on it The English alphabet is categorised into five groups, each starting with a vowel and encompassing the immediately following consonants in the group. Thus group one consists of A, B, C and D, group two consists of E, F,G and H, group three consists of 1, J, K, L, M and N, group four consists of O, P, Q,R, S and T, and the remaining letters make group five. These groups are assigned values as 10 for each letter of first group, 20 for each letter of second group, 30 for each letter of third group, 40 for each letter of fourth group, and 50 for each letter of group five. When used to form words, the value of each letter should be added up to compute the value of the word. If the word has letters only from the same group the value of the word would be the value of the sum of letters. However, if the letters in a word are from difierent groups, the value of the first letter of the word and any other letter of that group will be the same as that of its individual letter value of its group, but that of a letter from another group will be 'double’ as much as the value of each letter of its group. If we have to find the value of MANGO, its first letter is M (from third group), among A, N, G and O, N is also from third group. Hence value of M + N = 30 + 30 = 60 Now A, G and O belong to first, second and the fourth group respectively. Hence value of A + G + O = double the value of A + double the value of G + double the value of O = 2*10 + 2*20 + 2* 40 = 140. Hence, total value = 140+600 = 200.which one or two or three of the words denoted by A, B and C correspond to the given value. 270 (A)WORK (B)COPY (C)THIS 1) A and B only 2) B and C only 3) A and C only 5) All the three None of these