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Find the friction on the block in the fo...

Find the friction on the block in the following cases : (a)(b)(c )If(i) m = 0.1 kg and(ii) m = 1...

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Find the accelerations of blocks A and B for the following cases. (A) mu_(1)=0 " and "mu_(2)=0.1" (P)" a_(A)=a_(B)=9.5m//s^(2) (B) mu_(2)=0 " and "mu_(1)=0.1 " (Q)"a_(A)=9m//s^(2), a_(B)=10m//s^(2) (C) mu_(1)=0.1 " and "mu_(2)=1.0 " (R)"a_(A)=a_(B)=g=10m//s^(2) (D) mu_(1)=1.0 " and "mu_(2)=0.1 " (S)" a_(A)=1, a_(B)=9m//s^(2)

Two blocks of masses m_(1) = 10 kg and m_(2) = 20 kg are connected by a spring of stiffness k = 200 N/m. The coefficient of friction between the blocks and the fixed horizontal surface is mu = 0.1 . Find the minimum constant horizontal force F (in Newton) to be applied to m1 in order to slide the mass m_(2) . (Take g = 10 m//s^(2) )

Three blocks, placed on smooth horizontal surface are connected by ideal string and a disc shaped pulley of radius r, and mass m. Find the accelerations of the blocks. Masses of the blocks are given as M_(1) = 10kg, M_(2) = 5 kg , M_(3) = 2kg, m = 2kg .

In the arrangement shown in figure pulley P can move whereas other two pulleys are fixed. All of them are light. String is light and inextensible. The coefficient of friction between 2 kg and 3 kg block is mu = 0.75 and that between 3 kg block and the table is mu = 0.5 . The system is released from rest (i) Find maximum value of mass M, so that the system does not move. Find friction force between 2 kg and 3 kg blocks in this case. (ii) If M = 4 kg, find the tension in the string attached to 2 kg block. (iii) If M = 4 kg and mu_(1) = 0.9 , find friction force between the two blocks, and acceleration of M. (iv) Find acceleration of M if m_(1) = 0.75, m_(2) = -0.9 and M = 4 kg.

A block of mass m1 = 1 kg another mass m2 = 2 kg, are placed together (see figure) on an inclined plane with angle of inclination theta . Various values of theta are given in List I. The coefficient of friction between the block m_(1) and the plane is always zero. The coefficient of static and dynamic friction between the block m_(2) and the plane are equal to mu = 0.3 . In List II expressions for the friction on block m_(2) are given. Match the correct expression of the friction in List II with the angles given in List I, and choose the correct option. The acceleration due to gravity is denoted by g [Useful information : tan (5.5^(@)) ~~ 0.1, tan (11.5^(@)) ~~ 0.2 , tan (16.5^(@))~~ 0.3 ].

Block A has a mass of 2 kg and block B has a mass of 20 kg if the coefficient of kinetic friction between block B and the horizontal surface is 0.1, and B is accelerating towards the right with a = 2 m//s^(2) , then the mass of the block C will be -

In the arrangement shown in figure m_(A) = 4.0 kg and m_(B) = 1.0 kg. The system is released from rest and block B is found to have a speed 0.3 m/s after it has descended through a distance of 1m. Find the coefficient of friction between the block and the table. Neglect friction elsewhere. (Take g = 10 m/ s^(2) )

A 1.8kg block is moved at constant speed over a surface for which coefficient of friction mu=1/4 it is pulled by a force F acting at 45^@ with horizontal as shown in Fig. The block is displaced by 2 m. Find the work done on the block by (a) the force F (b) friction (c) gravity. .

Find the time taken by the block to reach the bottom of inclined plane. E= 200 hat(i) N/C , M=1kg , q=5mC,g= 10 m/s^2 mu =0.2