यदि a_(i)gt0 for iu=1, 2, 3, … ,n और a_(1)a_(2)…a_(n)=1, तो (1+a_(1))(1 का न्यूनतम मान +...

If a_(i)gt0 for i u=1, 2, 3, … ,n and a_(1)a_(2)…a_(n)=1, then the minimum value of (1+a_(1))(1+a_(2))…(1+a_(n)) , is

Q.if a_(1)>0f or i=1,2,......,n and a_(1)a_(2),......a_(n)=1, then minimum value (1+a_(1))(1+a_(2)),...,,(1+a_(n)) is :

If a_(1)gt0 for all i=1,2,…..,n . Then, the least value of (a_(1)+a_(2)+……+a_(n))((1)/(a_(1))+(1)/(a_(2))+…+(1)/(a_(n))) , is

If a_(1),a_(2),a_(3), . .. . ,a_(n) are in A.P. and a_(i)gt0 for each i=1,2,3, . . ..,n, then sum_(r=1)^(n-1)(1)/(a_(r+1)^(2//3)+a_(r+1)^(2//3)a_(r)^(1//3)+a_(r)^(1//3)) is equal to

If A_(i)=(x-a_(i))/(|x-a_(i)|),i=1,2,3,....n and a_(1)

If a_(1),a_(2),a_(3),"….",a_(n) are in AP, where a_(i)gt0 for all I, the value of (1)/(sqrta_(1)+sqrta_(2))+(1)/(sqrta_(2)+sqrta_(3))+"....."+(1)/(sqrta_(n-1)+sqrta_(n)) is

If a_(i) gt 0 AA I in N such that prod_(i=1)^(n) a_(i) = 1 , then prove that (a + a_(1)) (1 + a_(2)) (1 + a_(3)) .... (1 + a_(n)) ge 2^(n)

If quad 1,a_(1)=3 and a_(n)^(2)-a_(n-1)*a_(n+1)=(-1)^(n) Find a_(3).

Find the first five terms of the following sequences and write down the corresponding series (i) a_(n) = (1)/(5) (2n -3) (ii) a_(1) =a_(2) = 1 , a_(n) = a_(n-1) + a_(n-2) , n gt 2