यदि bara और barb दो सदिश इस प्रकार हैं कि |bara+barb|=|bara|, तो सिद्ध कीजिए कि 2bara+barb लंबवत...

IF bara times barb = barc and barb times barc=bara then

prove that: (baraxxbarb) ^ 2 = | bara | ^ 2 | barb | ^ 2 - (bara.barb) ^ 2 = | (bara.bara, bara.barb), (bara.barb, barb.barb) |

Prove that [bara+barb,barb+barc,barc+bara]=2[bara barb barc]

If bara is collinear with barb =3i + 6j + 6k and bara.barb=27 , then bara =

[[bara-barb, barb-bara, barc-bara]]=

If vectors bara,barb,barc are non-coplaner, then ( [ bara+2barb barb+2barc barc+2bara ] )//( [ bara barb barc ] ) =

If bara and barb be parrallel vectors, then [bara" "barc" "barb]=

If barc=bara times barb and barb=barc times bara then

Let bara barb barc be three unit vectors such that |bara+barb+barc|=1 and bara bot barb makes angles a and b with bara and barb respectively then cosa+cosb is equal to