प्रतिक्रिया,MnO_(4)^(-)+I^(-) longrightarrow I_(2)+ MnO_(2) स्टोइचीओम लेकर की जाती है...

The reaction, MnO_(4)^(-) + I^(-) longrightarrow I_(2) + MnO_(2) is carried out by taking stoichiometric quantities of KMnO_(4) in weak basic medium and KI.Number of moles of I_(2) produced for "4.0" mole of KMnO_(4) are

MnO_(2)+2KOH+(1)/(2)O_(2) to K_(2)MnO_(4)+H(2)O

MnO_(4)^(-) + 8H^(+) + 5e^(-) rightarrow Mn^(2+) + 4H_(2)O , E^(@) = 1.51V MnO_(2) + 4H^(+) + 2e^(-) righarrow Mn^(2+) + 2H_(2)O E^(@) = 1.23V E_(MnO_(4)^(-)|MnO_(2)

MnO_(4)^(2-) has "_____" geometry

In acidic medium,potassium manganate undergoes disproportionation according to equation. 3MnO_(4)^(2-)+4H^(+)longrightarrow2MnO_(4)^(-)+MnO_(2)+2H_(2)O Equivalent weight of K_(2)MnO_(4) will be (Mol.wt.of K_(2)MnO_(4) =M)