1.80 g of glucose (molar mas =180) is dissolved in 36.0g of water in a beaker. The total number ...

1.80 g of glucose (molar mas =180) is dissolved in 36.0 g of water in a beaker. The total number of oxygen atoms in the solution is

2.82g of glucose (molar mass =180 ) is dissolved in 30g of water. Calculate the (i) Molality of the solution (ii) mole fractions of (a) glucose (b) water.

If 3g of glucose (molecular mass 180) is dissolved in 60g of water at 15^(@)C , then the osmotic pressure of this solution will be :

If 23 g of glucose ( molecular mass 180)is dissolved in 60ml of water at 15^(@)C , then the osmotic pressure of this solution will be

10 g of glucose (molar mass 180) and 20 g of sucrose (molar mass 342) are dissolved in 100 g of water. What will be the vapour pressure of the resultant solution if the vapour pressure of water is 30 mm Hg ?

3.42 g of sucrose are dissolved in 18g of water in a beaker. The number of oxygen atoms in the solution are