`(0.101)_(2)` என்ற பகுதியின் தசம எண்ணைக் கண்டறியவும்.

(a+2b)^2+101( a+2b)+100

If average of 20 observation x_(1), x_(2), ……x_(20) is y . then the average of x_(1) - 101, x_(2) - 101, x_(3) - 101, ……. X_(20) - 101 is :

(2^(100))/(101) find Remainder.

(C_(0))/(1)+(C_(1))/(2)+(C_(2))/(3)+ . . . .+(C_(100))/(101) equals

If A=[(1,0,1),(0,0,0),(1,0,1)] , then find |A^(2)| .

(25.025)/(0.025) is equal to (a) 1.01 (b) 10.1(c)101 (d) 1001

If A = [ (0,1,1),(1,0,1),(1,1,0)] then A^(2) - 3I =