We have 200 mL of 6% urea solution at 27^(@)C. Osmotic pressure due to osmosis is (R=0.0821L ato...

A solution is prepared by dissolving 0.6 g of urea (molar mass =60 g"mol"^(-1) ) and 1.8 g of glucose (molar mass =180g"mol"^(-1) ) in 100 mL of water at 27^(@)C . The osmotic pressure of the solution is: (R=0.08206L "atm"K^(-1)"mol"^(-1))

18 g glucose and 6 g urea are dissolved in 1 L aqueous solution at 27^(@)C . The osmotic pressure of the solution will be a. 8.826 atm , b. 4.926 atm ,c. 2.92 atm , d. 4.42 atm

9g of glucose and 3g of urea are dissolved in 1L of solution at 27^(@)C .The osmotic pressure of the solution will be

(i) Prove that osmotic pressure is a colligative property. (ii) Calculate the molar of urea solution if it exerts an osmotic pressure of 2.45 atmosphere at 300K. (R = 0.0821 L atm. mol^(-1) K^(-1) ).

The osmotic pressure of one molar solution at 27^(@)C is

Two solutions of glucose have osmotic pressure 1.5 and 2.5 atm ,respectively. 1 L of first solution is mixed with 2 L of second solution. The osmotic pressure of the resultant solution will be a. 2.62 atm , b. 6.12 atm ,c. 3.26 atm , d. 2.16 atm

A solution obtained by mixing 100 mL of 20% solution of urea (molar mass =60) and 100 mL of 1.6% solution of cane sugar (molar mass =342) at 300 K . (R=0.083 L bar K^(-1) mol^(-1) ). Calculate a.Osmotic pressure of urea solution b.Osmotic pressure of cane sugar solution c.Total osmotic pressure of solution