সমীকরণ (ab)(x^2+y^2)-2a bx=0\nহবে যদি\r\nউৎপত্তি বিন্দুতে স্থানান্তরিত হয়...

Factorise: x^(2)-ax-bx + ab

(bx)/(a)-(ay)/(b)+a+b=0 and bx-ay+2ab

If y=bx^(2)+(a//x)" then "x^(2)y_(2)=

If bx^(2)+ay^(2)=(x+y)^(2)," then " (dy)/(dx)=

If ^(-1)(a^(2)x^(2)+b^(2)y^(2))+cos^(-1)|ax+bx|=pi if ab<0, then which of the following can be true-

The solution of differential equation xy^2(y_1^2+2)=2y_1y^3+x^3 , is (A) (x+y-a)(x^2-y^2-bx^2)=0 (B) (x^2-y^2-a)(x^2-y^2+bx^4)=0 (C) (x^2+y^2-a)(x^2+y^2-bx^4)=0 (D) none of these

abs(f(x)-f(y))le(x-y)^2 forall x,y in R and f(0)=1 then