CURRENT ELECTRICITY |Cells and Combination of Resistance |Class 12 Physics |6 PM By Abhinav Sir |L2

A sinusoidal voltage Vsin(at) is applied across a series combination of resistance R and inductor L. The amplitude of the current in the circuit is

As electric lamp and a conductor of resistance 4 Omega are connected in series to a 6 V battery. The current drawn by the lamp is 0.25 A. Find the resistance of the electric lamp.

Circuit Theory - Current Electricity | Physics for JEE, NEET, CLASS 12

The resistance of an electric bulb drawing 1.2 A current at 6 V will be

A cell of emf epsilon and internal resistance r gives a current of 0.5 A with an external resistance of 12 Omega and a current of 0.25 A with an external resistance of 25 Omega . Calculate (a) internal resistance of the cell and (b) emf of the cell.

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To get the maximum current from a parallel combination of n identical cells each of internal resistance r in an external resistance R , when

NEET 2020 - Revision In 60 Days | Class 12 | Current Electricity Part -2 | Quick Revision

In the electric circuit shown each cell has an emf of 2 V and internal resistance of 1Omega . The external resistance is 2Omega . The value of the current is (in A)