._(92)^(235)U ನಿಯಂತ್ರಿತ ಪರಮಾಣು ವಿದಳನಕ್ಕೆ ಒಳಗಾದಾಗ ಹೊರಸೂಸುವ ನ್ಯೂಟ್ರಾನ್‌ಗಳ ಸಂಖ್ಯೆ ._(5...

""_(92)^(235)U+X to Ba +Kr +3 ""_(1)^(0)n X is

""_(92)^(235)U, ""_(92)^(238)U and ""_(92)^(239)U are

A slow neutron strikes a nucleus of ._(92)^(235)U splitting it into lighter nuclei of ._(56)^(141)Ba and ._(36)^(92)Kr along with three neutrons. The energy released in this reaction is ( The masses of uranium, barium and krypton of this reaction are 235.043933,140.917700 and 91.895400 u respectively. The mass of a neutron is 1.008665 u

The number of neutrons emitted when ._(92)^(235)U undergoes controlled nuclear fission to ._(54)^(142)Xe and ._(38)^(235)U undergoes controlled nuclear fission to ._(54)^(142)Xe and ._(38)^(90)Sr is:

The isotope ._(92)^(235)U decays in a number of steps to an isotope of ._(82)^(207)Pb . The groups of particle emitted in this process will be:

Fill in the blanks: (a) ._(92)^(235)U + ._(0)^(1)n rarr ._(55)^(142)A + ._(37)^(92) B+.... (b) ._(34)^(82)Se rarr ... 2 ._(-1)e^(0)

In a nucleus reactor 0.96 grams of ._(92)U^(235) is consumed in one day. If 0.1% of mass of ._(92)U^(235) is available as energy fine the power of reactor (in MW )

When slow neutrons are incident on a target containing ._(92)U^(235) , a possitle fission reactionis ._(92)U^(235)+n rarr ._(56)Ba^(141)+_(36)Kr^(92)+3n+Q Estimate the amount of energy released using the following data : M[._(92)U^(235)]=235.04u, M[._(56)Ba^(141)]=140.91u, M[._(36)Kr^(92)]=91.926u, M_(n)=1.0087u. Take 1u=1.661xx10^(-27)kg. 1MeV=1.602xx10^(-13)J