ABC ত্রিভুজে, E হল মধ্যবিন্দু AD এর মধ্যবিন্দু। দেখাও যে `ar\\ (BED)=1/4a r\\ (ABC)` `...

In a ABC,E is the mid-point of median AD Show that ar(BED)=(1)/(4) ar (ABC)

In a triangle ABC, E is the mid-point of median AD. Show that ar (triangleBED)=1/4 ar( triangleABC ).

ABC is a triangle in which D is the midpoint of BC and E is the midpoint of AD. Prove that ar(triangleBED)=(1)/(4)ar(triangleABC) .

In a triangle ABC,E is the mid-point of median AD.Show that quad ar(BED)=(1)/(4)ar(ABC)

The vertex A of triangle ABC is joined to a point D on the side BC. The midpoint of AD is E. Prove that ar(triangleBEC)=(1)/(2)ar(triangleABC) .

In a triangle ' ABC,r_(-)1

In the given figure ar (Delta ABC)=" ar "(Delta ADE) . AC is the median of Delta ADE . If ar (ACE) =14 cm^(2)" then ar "(Delta ABC) = ?

ABC and BDE are two equilateral triangles such that D is the mid-point of BC. Then, ar (DeltaBDE) = (1)/(2) ar (DeltaABC) .

D, E, F are the midpoints of the sides BC, CA and AB respectively of triangle ABC. Prove that (i) BDEF is a ||gm, (ii) ar(triangleDEF)=(1)/(4) ar(triangleABC) and (iii) ar("||gm BDEF") = (1)/(2)ar(triangleABC)

In Fig.9.23,E is any point on median AD of a Delta ABC Show that ar (ABE)=ar(ACE)