The enthalpy of combustion of methane, graphite and dihydrogen at 298 K are, -890.3 kJ mol^(-1) ...

Calculate the enthalpy of formation of methane given that the enthalpies of combustion of methane, graphite and hydrogen are 890.2 KJ, 393.4 KJ and 285.7 KJ mol^(-1) respectively

If the enthalpy of combustion of diamond and graphite are -395.4 kJ mol^(-1) and -393.6 kJ mol^(-1) , what is enthalpy change for the C("graphite") rarr C("diamond") ?

The enthalpies of combustion of C_(("graphite")) and C_(("diamond")) are -393.5 and -395.4kJ//mol respectively. The enthalpy of conversion of C_(("graphite")) to C_(("diamond")) in kJ/mol is:

The heat of combustion of graphite and carbon monoxide respectively are 393.5 kJ mol^(-1) and 283 kJ mol^(-1) . Thus, heat of formation of carbon monoxide in kJ mol^(-1) is