70p আয়ে একটি ঘরের চার দেয়াল কাগজ করার খরচ\nপ্রতি বর্গমিটার হল R s.157.50।\n...

In Figure, P Q||R S , /_A E F=95^0, /_B H S=110^0 a n d /_A B C=x^0dot Then the value of x is (a)15^0 (b) 25^0 (c) 70^0 (d) 35^0

In Fig.103, P Q R S\ a n d\ /_P A B=60^0\ a n d\ /_A C S=100^0dot Then, /_B A C= (a) ( b ) (c) (d) (e) 40^(( f )0( g ))( h ) (i) (j) (b) ( k ) (l) (m) (n) 60^(( o )0( p ))( q ) (r) (s) (c) ( d ) (e) (f) (g) 80^(( h )0( i ))( j ) (k) (l) (d) ( m ) (n) (o) (p) 50^(( q )0( r ))( s ) (t) (u)

Consider the marks, out of 100, obtained by 51 students of a class in a test, given in Table 14.9. M a r k s"N u m b e r o f S t u d e n t s"0-10 5 10-20 10 20-30 4 30-40 6 40-50 7 50-60 3 60-70 2 70-80 2 80-90 3 90-100 9Tot a l 51 Draw a freque

The specific conductance in ohm- cm- of four electrolytes P, Q, R and S are given in brackets: {:(P(5.0 xx 10^(-5)),Q(7.0 xx 10^(-8))) ,(R(1.0 xx 10^(-10)),S(9.2xx 10^(-3))) :} The one that offer s highest resistance to the passage of electric current is:

In Fig.104, A B C D ,\ /_O A B=150^0\ a n d\ /_O C D=120^0dot Then, /_A O C= (a) ( b ) (c) (d) (e) 80^(( f )0( g ))( h ) (i) (j) (b) ( k ) (l) (m) (n) 90^(( o )0( p ))( q ) (r) (s) (c) ( d ) (e) (f) (g) 70^(( h )0( i ))( j ) (k) (l) (d) ( m ) (n) (o) (p) 100^(( q )0( r ))( s ) (t) (u)

Consider the A.P. 50,48,46,44 ……. If S _(n) denotes the sum to n terms of this A.R. then

The percentage of marks obtained by a student in the monthly unit tests are given below: U n i t t e s t : I I I I I I I V V P e r c e n t ag e of m a r k s ob t a i n e d : 58 74 76 62 85 Find the probability that the student gets: a first class i.e. at least 60% marks marks between 70% and 80% a distinction i.e. 75% or above less than 65% marks.

A student performs an experiment to determine how the range of a ball depends on the velocity with which it is projected. The "range" is the distance between the points where the ball lends and from where it was projected, assuming it lands at the same height from which it was projected. It each trial, the student uses the same baseball, and launches it at the same angle. Table shows the experimental results. |{:("Trail","Launch speed" (m//s),"Range"(m)),(1,10,8),(2,20,31.8),(3,30,70.7),(4,40,122.5):}| Based on this data, the student then hypothesizes that the range, R, depends on the initial speed v_(0) according to the following equation : R=Cv_(0)^(n) , where C is a constant and n is another constant. The student performs another trial in which the ball is launched at speed 5.0 m//s . Its range is approximately:

Study the following information carefully and answer the given questions based on it The English alphabet is categorised into five groups, each starting with a vowel and encompassing the immediately following consonants in the group. Thus group one consists of A, B, C and D, group two consists of E, F,G and H, group three consists of 1, J, K, L, M and N, group four consists of O, P, Q,R, S and T, and the remaining letters make group five. These groups are assigned values as 10 for each letter of first group, 20 for each letter of second group, 30 for each letter of third group, 40 for each letter of fourth group, and 50 for each letter of group five. When used to form words, the value of each letter should be added up to compute the value of the word. If the word has letters only from the same group the value of the word would be the value of the sum of letters. However, if the letters in a word are from difierent groups, the value of the first letter of the word and any other letter of that group will be the same as that of its individual letter value of its group, but that of a letter from another group will be 'double’ as much as the value of each letter of its group. If we have to find the value of MANGO, its first letter is M (from third group), among A, N, G and O, N is also from third group. Hence value of M + N = 30 + 30 = 60 Now A, G and O belong to first, second and the fourth group respectively. Hence value of A + G + O = double the value of A + double the value of G + double the value of O = 2*10 + 2*20 + 2* 40 = 140. Hence, total value = 140+600 = 200. CONCEPT 1)70 2)150 3)360 4)300 5)None of these